[Eeglablist] Frequency resolution of newcrossf
Arnaud Delorme
arno at ucsd.edu
Tue Jul 3 11:45:55 PDT 2018
Dear Bethel,
> I have:
> srate=1926Hz
> winlen=[0,1063]%i.e 2048 samples. So frequency resolution should be 1926/2048=0.9404
>
> pop_newcrossf( EEG, 1, 1, 2, [0 1063], [0] ,'type', 'phasecoher', 'title','Channel 1-2 Phase Coherence','padratio', 1,'freqs',[1,70],'detrend','on','rmerp','on’);
‘winsize' is the important parameter. This is the size of the sliding window. This determines the minimum frequency resolution when taken together with the number of cycles.
> " 'padratio' = FFT-length/winframes (2^k) {2}
> Multiplies the number of output frequencies by dividing
> their spacing (standard FFT padding). When cycles~=0,
> frequency spacing is divided by padratio.”
Padding ratio is FFT padding. It is a way to increase the number of frequencies returned (although it does not truly increase the resolution). I suggest you look at some of the lectures on the EEGLAB online tutorial.
Best wishes,
Arno
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