[Eeglablist] Dipole-Fitting - Behaviour of fitTwoDipoles
Nils Hachmeister
nils.hachmeister at uni-bielefeld.de
Mon Jun 12 00:45:48 PDT 2017
Hello everyone,
I'm a neuro-researcher from Bielefeld University, Germany. My question
is about the dipole fitting: As I understand, pop_multifit only ever
fits one dipole per IC (never two) and then the fitTwoDipoles adds a
second dipole to some ICs when some heuristic indicates a second dipole
would be beneficial, right?
When scanning through the dipoles in my data sets after running these
two function using the fine-fit EEGLAB GUI function, I realised that for
the vast majority of components with two dipoles the RV could be
decreased significantly by fitting position and moment (again). While
for single dipoles the RV never changed. Investigating this issue
further I realised that if I only fit dipoles' moment of a IC with two
dipoles nothing is changes. Hence, after adding the second dipole
fitTwoDipoles seems only to fit the dipoles' moment.
Furthermore I realised that the second dipole's position always seems to
be the mirror position of the first dipole, i.e. the sign of the first
coordinate of the original dipole's position is flipped. The first
coordinate describes the position in front-back-direction (along the
saggital axis, the dipole would, thus, be mirrored at the coronal
plane). It would have been my expectation that the dipole is mirrored in
left-right-direction (along the coronal axis, mirroring the dipole at
the saggital plane and thereby following the somewhat symmetric layout
of the brain). The symmetric dipoles check-box in the fine-fit-GUI seems
to do just that. Why does fitTwoDipoles behave differently?
This might also explain, why in very rare cases I observed that fitting
the (already added) second dipole increased the RV. As I understood it,
fitting dipoles really is an optimisation process aiming to minimise the
RV. Hence, hitting the "Fit dipole(s)' position and moment"-button
should never increase the RV. But if the dipole position to start with
is not considered a potential solution by the fine fit, this would
explain why.
Thanks in advance
Best Regards
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